An acid (x) reacts with a base (y) to produce mg3(po4)2. what are x and y?

A) ch4 + 2o2 —> co2 + 2h2ob) assuming stp, you will use the 22.4 l to convert to moles (22.4 l in one mole at stp), then convert between compounds using mole to mole ratio from the balanced equation for b c & dyou have 0.650 l of ch40.650 l = 1 mole ch4 = 0.029 moles ch4 22.4 l ch4now use mole ratio to convert ch4 to o2(ratio of 1 mole ch4 for every 2 moles o2)0.029 moles ch4 = 2 moles o2 = 0.058 1 mole ch4now change back to liters 0.058 mole o2 = 22.4 l o2 = 1.3 l o2 1 mole o2c) 0.029 moles ch4 = 1 mole co2 = 0.029 1 mole ch4(0.029 moles ch4 is used again since if we start with 0.650 l of ch4 the mole will be 0.029, just saves calculations : ) ) 0.029 mole co2 = 22.4 l co2 1 mole co2= 0.65 l co2d) 0.029 mole ch4 = 2 mole h2o = 0.058 1 mole ch40.058 mole h2o = 22.4 l h2o = 1.3 l h2o 1 mole h2o

Helium is found in the 1st period of the periodic table. it also is part of the noble gases group in the last column (18th) of the table.