Asample of 0.300 mg pure chromium was added to excess hydrochloric acid to form a 10.0 ml aqueous solution of a chromium (iii) salt, which has a violet hue. exactly 1.00 ml of the resulting solution was analyzed using a spectrophotometer in a 1.00-cm cell at 575 nm, and the percent transmittance for the solution was 62.5%. what is the extinction coefficient?
since the ball bounces higher when the ball is ats its highest peak, their is potential energy
water pipes burst because the water inside them expands is it gets close to freezing, and this causes an increase in pressure inside the pipe. when the pressure gets too high for the pipe to contain, it ruptures.
1. calculate the mass of each element
mass of c = 1.45 mg co₂ × (12.01 mg c/44.01 mg co₂) = 0.3957 mg c
mass of h = 0.89 mg h₂o × (2.016 mg h/18.02 mg h₂o) = 0.0996 mg h
mass of o = mass of compound - mass of c - mass of h = (1.55 – 0.3957 – 0.0996) mg = 1.055 mg
2. calculate the moles of each element
moles of c = 0.3957 mg c × 1mmol c/12.01 mg c = 0.03295 mol c
moles of h = 0.0996 mg h × 1 mmol h/1.008 mg h = 0.0988 mol h
moles of o = 1.055 mg o × 1 mmol o/ 16.00 mg o = 0.06592 mol o
3. calculate the molar ratios
divide all moles by the smallest number of moles.
c: 0.032 95/0.032 95 = 1
h: 0.0988/0.032 95 = 2.998
o: 0.065 92/0.032 95 = 2.001
4. round the ratios to the nearest integer
c: h: o = 1: 3: 2
5. write the empirical formula
the empirical formula is ch₃o.