answer: the atomic mass of the second isotope of boron (b) is 11.01 amu.
explanation:the average atomic mass is can be calculated by the summation of the product of the atomic mass of each isotope multiplied by its abundance (abundance % / 100.0).boron has two isotopes:
1) at.mass = 10.012938 amu ≅ 10.013 amu and its abundance = 0.198
2) at.mass = amu and its abundance = 0.802
average atomic mass of boron = 10.81 amu.the average atomic mass of boron = (10.013 amu)*(0.198) + (atomic mass of the second isotope amu)*(0.802) = 10.81 amu10.81 = 1.9825 + (0.802 x atomic mass of the second isotope)(0.802 x atomic mass of the second isotope) = 10.81 - 1.9825 = 8.8275.atomic mass of the second isotope = 8.8275 / 0.802 = 11.0068 ≅ 11.01 amu.
the volume of fluid displaced would equal the volume of the gas. use a gas syringe - this is a laboratory instrument that can be used to withdraw a certain volume of gas from a closed system or to measure the volume of gas from a chemical reaction.
c. h2o is reduced
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