For the reaction below, determine the standard free energy change, δg o. cu(s) + sn2+(aq) → cu2+(aq) + sn(s) e o cell =–0.48 v view available hint(s) for the reaction below, determine the standard free energy change, δg o. cu(s) + sn2+(aq) → cu2+(aq) + sn(s) e o cell =–0.48 v −92.6 kj 92.6 kj −46.3 kj 46.3 kj
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d. c6h12o6 i believe is your answer
this is known that the number of moles of solute will remain the same even on dilution.
the relation between mole and molarity is
so the moles before and after dilution will be equated as:
m1=initial molarity = 15.9 m
v1= initial volume = ?
m2= final molarity = 5 m
v2 = final volume = 1.80 l
thus we will take 0.566 l of concentrated nitric acid and will dilute it to 1.8 l.
answer: -792 kj.
explanation:to get δh of the reaction: 2s + 3o₂ → 2so₃ the sum of the two mentioned equations should give the result of the reaction we need to calculate its δh.we multiply the first equation by 2 and also its δhrxn:
2s + 2o₂ → 2so₂ δhrxn = -594 kjand reverse the second reaction and so, multiply the δhrxn by -1:
2so₂ + o₂ → 2so₃ δhrxn = -198 kjby summing the two reactions, we get the reaction that we need to calculate its δhrxn: 2s + 3o₂ → 2so₃ now, we can apply hess's law says that δh is a state function that do not depend on the path of the reaction but depends on the initial and final state.δhrxn = δh of the first reaction + δh of the second reaction δhrxn = (-594 kj) + (-198 kj) = -792 kj.