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Chemistry, 02.12.2019 23:20

Given thath2(g) + f2(g) -> 2hf(g) => ∆h = -546.6 kj . mol-12h2(g) + o2(g) -> 2h20(l) => ∆h = -571.6 kj. mol-1

calculate the value of ∆h for: 2f2(g) + 2h20(l) -> 4hf(g) + o2(g)

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Given thath2(g) + f2(g) -> 2hf(g) => ∆h = -546.6 kj . mol-12h2(g) + o2(g) -> 2h20(l) =&g...
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