How do you find the iupac name for a compound like zno
we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to
now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.
we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.
this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.
a) 2mg + ticl₄ ⟶ 2mgcl₂ + ti
b) 1.02 kg
a) balanced equation
we know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
m_r: 24.30 47.87
2mg + ticl₄ ⟶ 2mgcl₂ + ti
b) mass of mg
(i) calculate the moles of ti
n = 1.00 kg ti × (1 kmol ti /47.87 kg ti)
= 0.020 89 kmol ti
(ii) calculate the moles of mg
the molar ratio is (2 kmol mg/1 kmol ti)
n = 0.020 89 kmol ti × (2 kmol mg/1 kmol ti)
= 0.041 78 kmol mg
(iii) calculate the mass of mg
m = 0.041 78 kmol mg × (24.30 kg mg/1 kmol mg)
= 1.02 kg mg
you need 1.02 kg mg to produce 1.00 kg ti.