according to the molar ratio in the equation, for every 1 mole of hcl, 1 mole of nacl is formed.
thus, if 1.9 mol of hcl is used up in the reaction, 1.9 mol of nacl is formed.
so the answer is 1.9 mol of nacl.
answer: the atomic mass of the second isotope of boron (b) is 11.01 amu.
explanation:the average atomic mass is can be calculated by the summation of the product of the atomic mass of each isotope multiplied by its abundance (abundance % / 100.0).boron has two isotopes:
1) at.mass = 10.012938 amu ≅ 10.013 amu and its abundance = 0.198
2) at.mass = amu and its abundance = 0.802
average atomic mass of boron = 10.81 amu.the average atomic mass of boron = (10.013 amu)*(0.198) + (atomic mass of the second isotope amu)*(0.802) = 10.81 amu10.81 = 1.9825 + (0.802 x atomic mass of the second isotope)(0.802 x atomic mass of the second isotope) = 10.81 - 1.9825 = 8.8275.atomic mass of the second isotope = 8.8275 / 0.802 = 11.0068 ≅ 11.01 amu.