Use the distributive property to
27 nuetrons and 30 protuens
a) pto₂ + 2h₂ ⟶ pt + 2h₂o
b) 0.021 g
c) 0.010 mol; 0.18 g
a) balanced equation
we know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
m_r: 2.016 195.08 18.02
pto₂ + 2h₂ ⟶ pt + 2h₂o
b) mass of h₂
(i) calculate the moles of pt
n = 1.0 g pt × (1 mol pt /195.08 g pt)
= 5.13 × 10⁻³ mol pt
(ii) calculate the moles of h₂
the molar ratio is (2 mol h₂/1 mol pt)
n = 5.13 × 10⁻³ mol pt × (2 mol h₂/1 mol pt)
= 0.0103 mol h₂
(iii) calculate the mass of h₂
m = 0.0103 mol h₂× (2.016 g h₂/1 mol h₂)
m = 0.021 g h₂
you need 0.021 g h₂ to produce 1.00 g pt.
c) moles of water
the molar ratio is (2 mol h₂o/1 mol pt)
moles of h₂o = 5.13 × 10⁻³ mol pt × (2 mol h₂o/1 mol pt)
= 0.010 mol h₂o
mass of water = 0.010 mol h₂o × (18.02 g h₂o/1 mol h₂o)
= 0.18 g h₂o
in a sugar crystal, the sucrose molecules are arranged in a repeating pattern that extends in all three dimensions, and all of these molecules are attracted to each other by inter-molecular forces that is a type of interaction that binds molecules together and is weaker than the bonds between atoms in a molecule.
the bond between the oxygen and hydrogen atoms (o–h bond) in sugar (sucrose) gives the oxygen a slight negative charge and the hydrogen a slight positive charge.the polar water molecules attract the negative and positive areas on the polar sucrose molecules which makes sucrose dissolve in water.
answer: a) 1
explanation: rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.