What is the maximum amount of potassium nitrate (kno 3) that can dissolve in 100 grams of water at 40°c?
need no plzzz !
here we have to compare the bohr atomic model with electron cloud model.
in the bohr's atomic model the electrons of an element is assumed to be particle in nature. which was unable to explain the debroglie' hypothesis or the uncertainty principle and has certain demerits.
the uncertainty principle reveals the wave nature of the electrons or electron clod model. the bohr condition of a stable orbits of the electron can nicely be explained by the electron cloud model, the mathematical form of which is λ = nh/mv, where, λ = wavelength, n is the integral number, h = planck's constant, m = mass of the electron and v = velocity of the electron.
the integral number i.e. n is similar to the mathematical form of bohr's atomic model, which is mvr = nh/2π. (r = radius of the orbit).
thus, the electron cloud model is an extension of the bohr atomic model, which can explain the demerits of the bohr model. later it is revealed that the electron have both particle and wave nature. which is only can explain all the features of the electrons around a nucleus of an element.
the unnamed spacecraft which travels to mars, will have the greatest weight on the earth.
answer : the density of metal is, 2.7 g/ml
solution : given,
mass of metal = 4.86 g
volume of initial water = 15.5 ml
volume of rose water = 17.3 ml
first we have to calculate the volume of metal.
volume of metal = volume of rose water - volume of initial water
volume of metal = 17.3 - 15.5 = 1.8 ml
now we have to calculate the density of metal.
formula used :
now put all the given values in this formula, we get the density of metal.
therefore, the density of metal is, 2.7 g/ml
i₂ (g) + br₂ (g) ↔ 2ibr (g)
given is kc = 280 at 150 degree c.
kc = [ibr]² / [i₂][br₂]
initially [ibr] = 0.45 / 2 = 0.225 m
the actual reaction is:
2ibr ↔ i₂ + br₂, kc = 1/280 = 0.00357142
[ibr] = 0.225 - 2x
[i₂] = x
[br₂] = x
by substituting the values we get,
k = [i₂] [br₂] / [ibr]²
0.00357142 = x×x / (0.225 - 2x)²
√(0.00357142) = x / (0.225 - 2x)
0.0597613 (0.225 - 2x) = x
0.01344 - 2 × 0.0597613x = x
(1 + 2 × 0.0597613)x = 0.01344
x = 0.01344 / (1+2 × 0.0597613)
x = 0.01344 / 1.1195226
x = 0.012005
substituting the values we get,
ibr = 0.225 - 2 × 0.012005 = 0.17698 m
i₂ = x = 0.012005 m
br₂ = 0.012005 m