Arrange these numbers from least to greatest: 2 over 5 comma text end text − 3 over 7 comma text end text 2 over 3.

a.
2 over 5 comma text end text − 3 over 7 comma text end text 2 over 3

b.
− 3 over 7 comma text end text 2 over 5 comma text end text 2 over 3

c.
− 3 over 7 comma text end text 2 over 3 comma text end text 2 over 5

d.
2 over 5 comma text end text 2 over 3 comma text end text text ​ end text − 3 over 7

my best interpretation of this is that you're given a geometric progression consisting of terms, the first of which is and the last of which is . (so we don't actually know right away how many terms there are.) the common ratio between terms is . you want to find the sum of all terms.

in a geometric progression, the -th term is determined by the previous term according to

starting with , we find

and so on. the general pattern for the -th term is then

the last term in the sequence is , so

the sum of these terms is given by

notice that

with and , we get a sum of

answer:

step-by-step explanation:

let n represent the number

twice the number =2n

4 times the number = 4n

given that twice the number is atleast 3 less than four times the number

algebraically this can be written as

2n≤4n-3

we can add 3 to both sides

so n should be atleast 1.5

if n is natural number or integer then least value of n is 2.