Astudy was conducted to determine the mean birth weight of a certain breed of kittens. consider the birth weights of kittens to be normally distributed. a sample of 45 kittens was randomly selected from all kittens of this breed at a large veterinary hospital. the birth weight of each kitten in the sample was recorded. the sample mean was 3.56 ounces, and the sample standard deviation was 0.2 ounces. what is the margin of error for a 90% confidence interval on the mean birth weight of all kittens of this breed.
choice a is correct answer.
given expression is :
we have to represent above expression in factored form.
as we have noticed that the expression contains the multiples of 3.
taking 3 as common from given expression,we get
now, spit the middle term of above expression so that the product of two terms should be 8 and their sum be 6.
making two groups and taking two terms as common,we get
taking (x+4) as common,we get
3(x+4)(x+2) which is the factored form of 3x²+18x+24.
the answer is $80 / $60
we can use the properties of similar triangles.
16/8 = 30/x
2 = 30/x multiply each side by x
2x = 30 divide each side by 2
x = 15 ft
the shadow is 15 ft long.
16/8 = 30/15
2 = 2