Astudy was conducted to determine the mean birth weight of a certain breed of kittens. consider the birth weights of kittens to be normally distributed. a sample of 45 kittens was randomly selected from all kittens of this breed at a large veterinary hospital. the birth weight of each kitten in the sample was recorded. the sample mean was 3.56 ounces, and the sample standard deviation was 0.2 ounces. what is the margin of error for a 90% confidence interval on the mean birth weight of all kittens of this breed.

step-by-step explanation:

its b because if u listen in math class u would no nooooooob

answer:

bill suffered a loss of 42.85%.

step-by-step explanation:

bill bought a home for $210000 and sold it for $120000 and we have to calculate the percentage loss he suffered.

as we know loss suffered = difference of sale price and cost price of the home.

total loss = 210000-120000 = $90000

now percentage loss =

= 9/21×100 = 3×100/7 = 42.85%

so the answer is 42.85% loss.

answer:

y= -4x+4

step-by-step explanation:

y= mx+c is slope-intercept form of equation of line where m is slope and c is y-intercept.

in question statement,we observe that

x-intercept: (1,0)

y-intercept: (0,4)

we have to find slope for line.

slope= m =

slope= m = 4-0/0-1

slope = m = 4/-1

slope = m = -4

y-intercept= c = 4

putting the values of slope and y-intercept in slope intercept form,we get

y= -4x+4 is equation of line that has intercepts (1,0) and (0,4).