threofvnd tthidhff erefkopdl.gaekj vpremrajrrt oi ng d iedeflsc
discriminant is 36.
x²-4x-5 = 0 have two real solutions.
given equation is :
we have to find discriminant of above equation.
general quadratic equation is :
ax²+bx+c = 0
comparing general equation with quadratic equation,we get
a = 1 ,b= -4 and c = -5
the formula to find discriminant is :
d = b²-4ac
putting the values of a,b and c in formula to find discriminant,we get
d = (-4)²-4()
d = 16+20
d = 36 > 0
if an equation has discriminant real and perfect square ,there are exactly two real solutions.
hence, 36 is real and greater than zero,so give equation have two real solution.