Factor completely.

-2k - k 3 - 3k 2

a: k(-k + 1)(k - 2)

b: -k(k -...

Mathematics, 10.04.2019 01:46 sydneip6174

# Factor completely.

-2k - k 3 - 3k 2

a: k(-k + 1)(k - 2)

b: -k(k - 1)(k - 2)

c: -k(k + 1)(k + 2)

Answers: 3

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