h = 2y^6 +7
put the given values into the formula and solve for the unknown.
v = lwh
(20y^10 +70y^4) = (2y^3)·(5y)·h
divide by the coefficient of h.
(20y^10 +70y^4)/(10y^4) = h = 2y^6 +7
the rules of exponents apply. here, you need the ones that say(a^b)·(a^c) = a^(b+c)(a^b)/(a^c) = a^(b-c)
let's solve this by elimination, then substitution.
x= adult ticket
y= student ticket
first day: 14x + 8y = 376
second day: 7x + 11y = 272:
divide 14x+8y=376 by -2:
eliminate both -7x and 7x:
add all numbers:
divide both sides by 7/ divide 84 by 7:
now substitute y into one of the equations:
subtract both sides by 132:
divide both sides by 7 (140/7):
adult tickets: $20
student tickets: $12
15 of them are green.