answer: option d is correct .
in order to find the same attendance we set both equation equal
8x+191 = -x^2+26x+126
simplifying equation ,we get
(x-5) (x-13) = 0
x =5 or x =13
therefore on 5th day and 13th day both plays attendance is same
and it is obtained by plugging x = 5 in and x =13 in either of the equation.
for x = 5 ,
y = 8(5) +191 = 40+191 = 231
for x = 13
y = 8(13)+191
therefore option d is correct
(21 . 7 . 3)x.
that would be (21 . 7 . 3)x.
the associative property allows us to multiply regardless of how the numbers/variables are grouped. we can put the parentheses anywhere.
4x - 6 = 3x + 8.
if the number is x then 4 times is 4x , then - 6 gives us 4x - 6.
similar reasoning gives us 3x + 8.
part i: graph the following points...