discriminant is 36.
x²-4x-5 = 0 have two real solutions.
given equation is :
we have to find discriminant of above equation.
general quadratic equation is :
ax²+bx+c = 0
comparing general equation with quadratic equation,we get
a = 1 ,b= -4 and c = -5
the formula to find discriminant is :
d = b²-4ac
putting the values of a,b and c in formula to find discriminant,we get
d = (-4)²-4()
d = 16+20
d = 36 > 0
if an equation has discriminant real and perfect square ,there are exactly two real solutions.
hence, 36 is real and greater than zero,so give equation have two real solution.
i'm not sure but 13" by 6.5"?