If the car had not hit the fence, how much farther would it have skidded? solve the skid-distance formula to find the extra distance that the car would have traveled if it had not hit the fence. round your answer to two decimal places. note that unit conversion is built into the skid distance formula, so no unit conversions are needed.
i know there is an easier way to do but i am gonna show you a way that i can remember best.
first you want to find the height and base. of a square, that is isn't to hard since the height is equal the base.
so, squareroot 300.
which is about 17.3
now we are gonna do the pythagorean theorem.
a^2 + b^2 = c^2
so replace a and b with 17.3
17.3^2 + 17.3^2 = c^2
okay, so now square 17.3-- oh look, we already have it.
300 + 300 = c^2
300 + 300 = 600 (which now we need to squareroot 600 to get our c alone.
squareroot of 600= 24.5
so it is 24.5m
in the abscissa (x), a is in the middle point between 0 and 5:
in the ordinate (y), a is in the middle point between 9 and 12:
then, the coordinates of point a are:
rate = distance/time
= 4000 /12.089
= 330.88 m/min
domain = x ∈ r
minimum = (-7/18, 59/36)
vertical intercept ( 0, 3 )