Shift y= 5√x +3 horizontally 2 units to the right and stretched by a factor of 3 (stretched vertically about the fixed y=3 line)
|y + 6| = 2
this means y + 6 = 2 or y + 6 = -2 giving y = -4 , y = -8.
so we have 2 solutions.
the solution to -(y + 6) will also be a solution to the absolute equation.
the solutions will be the numbers on the number line 2 units away from -6.
y= -2× -1