Squestion 2 of 5
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let p(x) = 9x° – 3x + 1x' and q(x) = 90° + 3x3 + 80x. which of the following is
equivalent to p(x) +q(a)?
3x(63% + 2x2 + 27)
@
3r(67% + 27)
3x(
67 + 272)
38(6241 + 22+ 272)

it is 87.5% decrease

answer:

0

step-by-step explanation:

five times 0 equals 0 plus 6 would equal 6

answer:

∠dae is the smallest

step-by-step explanation:

in any triangle

• the angle opposite the shortest side in the triangle is the smallest

• the angle opposite the longest side is the largest

hence

smallest angle is ∠dae and largest angle is ∠ade

answer:

  the first equation can be multiplied by 2.

step-by-step explanation:

the x-coefficients are -2 and 4. if the first one of these is multiplied by 2, it will be the opposite of the second of these. that is 2·(-2) = -4. when -4 and 4 are added, the result is 0, so the x-variable will be eliminated.

to solve these equations by "elimination", you look for simple relationships between the coefficients that will let you combine them to get zero.

here's the rest of the solution.

  2(-2x-5y) +(4x+2y) = 2(-1) +(8) . . after multiplying the first equation by 2 and adding the second equation

  -4x -10y +4x +2y = -2 +8 . . . the result of eliminating parentheses

  -8y = 6 . . . the result of collecting terms

  y = -6/8 = -3/4 . . divide by the y-coefficient

since all of the coefficients in the second equation are even, a factor of 2 can be removed, and the equation written as

    2x +y = 4

this can be solved for x, so you have

  x = (4 -y)/2 = 2 -(y/2)

filling in the above value of y, we find x to be

  x = 2 /4)/2

  x = 2 3/8

comment on eliminating y instead of x

if you divide the second equation by 2 so that y has a coefficient of 1, then you can multiply this equation by 5 to give y a coefficient that is the opposite of the coefficient -5 in the first equation. then the elimination looks like

  (-2x -5y) +5(2x +y) = (-1) +5(4)

  -2x -5y +10x +5y = -1 +20 . . eliminate parentheses

  8x = 19 . . simplify

  x = 19/8 = 2 3/8 . . divide by the coefficient of x