Steven has 9 gold coins that are identical in appearance. however, one coin is counterfeit and weighs slightly less than the others. using a balance scale, how can he find the counterfeit coin in just two weighings?
split the coins into three groups, a, b and c consisting of 3 coins in each group.
1. if a=b, the the counterfeit is in group c
weigh any two coins in group c and figure out the rest.
2. if a≠b, then the counterfeit is in the lighter group.
weigh any two coins in the lighter group and figure out the rest.
"ratio of wooden bats to metal bats is 2 to 1" basically means "there are twice as many wooden bats (compared to metal ones)". so if we had 3 metal bats, then we'd have 2*3 = 6 wooden bats. if we had 7 metal bats, then we have 14 wooden ones (because 2*7 = 14). and so on. the basic rule is to multiply the amount of metal bats by 2 to get the amount of wooden ones.
we can go in reverse to divide the amount of wooden bats to get the amount of metal ones. so 20/2 = 10 is the amount of metal bats.
a more formal approach is to use the proportion below to solve for x
20/x = 2/1
20*1 = x*2
20 = 2x
2x = 20
2x/2 = 20/2
x = 10
and we get the same answer.
hey there!for the first step you'll have to find your common multiples of each of the factors that you may have then, look for your variables in the terms/ between each of the factors once when you do that, factor it (like the pairs that factor out)
now, let's solve your particular equation now→ and also, → then, find your common factors, which is: there's more steps to solve this, but it will take a while to solve itso,
good luck on your assignment and enjoy your day!