The half life of carbon-14 is 5,730 years, assuming you start with 100% of carbon-14, what is the expression for the percent, p(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 20,000 years old?
hint: the exponential equation for half life s p(t)=ao(0.5)^t/h, where p(t) is the percent of carbon-14 remaining, ao, is the initial amount (100%), t is age of organism in years, and h is the half life.
a. p(t)=100(0.5)^5,730t, 29% remaining
b. p(t)=100(0.5)^5,730/t, 91% remaining
c. p(t)= 5,730(0.5)^100t, 5,710 remaining
d. p(t)=100(0.5)^t/5,730, 9% remaining
23 child tickets were sold
using the information given, we can set up an equation to solve for the number of child tickets sold. since there were three times as many adult tickets as child tickets sold, we can assign the variable 'x' to represent the number of child tickets and '3x' to represent the number of adult tickets. since we know the cost of each ticket, as well as the total sales, we can set up the following equation:
5.20x + 9.70(3x) = 788.90
simplify 5.20x + 29.1x = 788.90
combine like terms: 34.3x = 788.90
divide both sides by 34.3: x = 23 child tickets
domain = x ∈ r
minimum = (-7/18, 59/36)
vertical intercept ( 0, 3 )