The strength of a certain type of rubber is tested by subjecting pieces of the rubber to an abrasion test. for the rubber to be acceptable, the mean weight loss μ must be less than 3.5 mg. a large number of pieces of rubber that were cured in a certain way were subject to the abrasion test. a 95% upper confidence bound for the mean weight loss was computed from these data to be 3.45 mg. someone suggests using these data to test h0 : μ ≥ 3.5 versus h1 : μ < 3.5. it is discovered that the mean of the sample used to compute the confidence bound is x⎯⎯⎯ = 3.40. is it possible to determine whether p < 0.01? explain. round the test statistic to two decimal places and the answer to four decimal places.
solutions of the given equations is (-3,2).
here the equations given are y = -x²-6x-)
and y = )
now we substitute the value of y from equation (2) into (1)
2 = -x²-6x-7
x²+6x+7 = -2
x²+6x+7+2 = 2-2
x²+6x+9 = 0
x²+3x+3x+9 = 0
x(x+3)+3(x+3) = 0
(x+3)(x+3) = 0
therefore value of x is x = -3
therefore the solution is (-3,2).