in order for three line segments to form a triangle with non-zero area, they must satisfy the "triangle inequality." there are several ways to express this, but perhaps the simplest is
a + b > c
where a, b, and c are the lengths of sides in order from shortest to longest.
here, that means the requirement for a triangle is
4 + 4 > 7 . . true, so a triangle can be formed
the triangle inequality is satisfied by these segment lengths.
27/ (3+6) x 5 - 12
27/9 x 5 - 12
3 x 5 - 12
15 - 12
pemdas. do what is in parenthesis first, then divide/multiply, reading from left to right, then add/subtract reading from left to right.
the y value for the point located 3 over 4 the distance from r to s is 23/4=5.75
initial point: r=(1,2)=(xr,yr)→xr=1, yr=2
final point: s=(6,7)=(xs,ys)→xs=6. ys=7
point: p=(x,y), y=?
and the ratio:
r=(3/4)rs / [(1/4)rs]
r=(3/4) / (1/4)
median = the interquartile range (iqr) = 16