For a very rough pipe wall the friction factor is constant at high reynolds numbers. for a length l1 the pressure drop over the length is p1. if the length of the pipe is then doubled, what is the relation of the new pressure drop p2 to the original pressure drop p1 at the original mass flow rate?
answer; ////(a)///100kg 1.0m
1. the positioning of the sun
3. summer solstice
the net force on the climber is 495 n acting downwards direction.
the forces acting on the climber are:tension = 455 ngravity = mass × acceleration due to gravity = 95 kg × 10 m/s² = 950 kg-m/s²
now, the net force on the climber = gravity - tension
= 950 n - 455 n
= 495 n
(this force acts downwards as the force of gravity acts downwards)