Near the surface of the earth, objects in free fall (but not terminal velocity) experience a. constant distance. b. constant acceleration. c. constant speed. d. constant velocity.
the mass is attached to the spring vertically, so at equilibrium the force of gravity pulling down on the mass will equal the spring force acting upwards on the mass.
f = mg
m is the mass.
g is the acceleration due to earth's gravity.
for the spring:
f = kδx
k is the spring constant.
δx is the spring extension.
set the force of gravity and spring force equal to each other:
mg = kδx
m = 8.4 kg
g = 9.81 m/s²
k = 4.7 n/m
substitute the terms in the equation with the given values and solve for δx:
8.4×9.81 = 4.7δxδx = 17.53 m
here at the moment when bullet strikes the block it will have no external force on it
so here we can use momentum conservation
so we will have
so they move together with speed 1.98 m/s